The current size of an image on Sandra's computer is shown below:

A rectangle is shown. The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

What are the dimensions of the image at fraction 1 over 2 times its current size?

A. Length = 4 inches, width = 6 inches
B. Length = 3 inches, width = 4 inches
C. Length = 8 inches, width = 10 inches
D. Length = 12 inches, width = 16 inches

Respuesta :

6*1/2=3
8*1/2=4
Length= 3 inches
width= 4 inches
Answer : B

Answer:

Option B is correct

Length = 3 inches, width = 4 inches

Step-by-step explanation:

As per the statement:

The current size of an image on Sandra's computer is shown below:

A rectangle is shown:

The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

⇒Length(l) = 6 inches and width(w) = 8 inches

We have to find the dimension of the image at fraction 1 over 2 times its current size.

Dimensions of the image at [tex]\frac{1}{2} \times \text{Current Size}[/tex]

then;

[tex]\text{Length} = \frac{1}{2} \times \text{Current size of length}=\frac{1}{2} \times 6 =3[/tex] inches

and

[tex]\text{Width} = \frac{1}{2} \times \text{Current size of width}=\frac{1}{2} \times 8 =4[/tex] inches

Therefore, the dimensions of the image at fraction 1 over 2 times its current size are:

Length = 3 inches, width = 4 inches