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What is the period, in seconds, of a simple pendulum of length 5 meters? Use the gravitonal constant g=9.8m/s^2 and round your answer to two decimal places

Respuesta :

T = 2π√(l/g) 

=> T = 2π√[5m/(9.8m/s²)] 

=> T ≈ 4,49s 

The Time period of the simple pendulum will be = 4.48 sec

What is time period of a simple pendulum ?

It is the time taken by the production to finish one full oscillation .

Its general formula is

Time period (T) = 2π[tex]\sqrt{l/g}[/tex]

given : length(l) = 5m

           gravitational constant (g) =9.8m/s^2

substituting the values of l and g

Time period = 2* 3.14 [tex]\sqrt{5/9.8}[/tex]

Time period = 2 * 3.14 * 0.714

Time period = 4.48 sec

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