Answer: The chlorate ion concentration in the solution is 0.080 M
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Mass of solute (potassium chlorate) = 3.682 g
Molar mass of potassium chlorate = 122.55 g/mol
Volume of solution = 375 mL
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{3.682g\times 1000}{122.55g/mol\times 375mL}\\\\\text{Molarity of solution}=0.080M[/tex]
The chemical equation for the ionization of potassium chlorate follows:
[tex]KClO_3\rightarrow K^++ClO_3^-[/tex]
1 mole of potassium chlorate produces 1 mole of potassium ions and 1 mole of chlorate ions
So, concentration of chlorate ions in the solution = 0.080 M
Hence, the chlorate ion concentration in the solution is 0.080 M
