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To practice problem-solving strategy 6.1 circular dynamics problems a 1500-kg car drives at 30 m/s around a flat circular track 300 m in diameter. what are the magnitude and direction of the net force on the car?

Respuesta :

Tharindu
zero..... there are equal forces on the car which directions are oppsite. one is centrafuganl force, other one is frictional force

Answer:

it will have net force of 4500 N towards the center of the circular path

Explanation:

When an object moves in circular path at constant speed then the net force on the object is always towards its center of the path

This force is known as centripetal force

It is given by

[tex]F_c = \frac{mv^2}{R}[/tex]

[tex]F_c = \frac{1500 (30^2)}{300}[/tex]

[tex]F_c = 4500 N[/tex]

so it will have net force of 4500 N towards the center of the circular path

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