Respuesta :
Rewrite the first equation to be in y=... form:
2x+3y=2
3y = 2-2x
y = (2-2x)/3
Now you can equate it to the second (the y drops out):
(2-2x)/3 = x+3
2/3 - 2/3x = x + 3
-5/3x = 7/3
x = - 7/5
so y = x+3 = -7/5 + 3 = 8/5
The intercept is at (-7/5, 8/5)
2x+3y=2
3y = 2-2x
y = (2-2x)/3
Now you can equate it to the second (the y drops out):
(2-2x)/3 = x+3
2/3 - 2/3x = x + 3
-5/3x = 7/3
x = - 7/5
so y = x+3 = -7/5 + 3 = 8/5
The intercept is at (-7/5, 8/5)