Respuesta :
This problem involves only one variable, so we stick to one horizontal line, which represents p values. There is no vertical axis.
If 4p+1>-7, we solve for p by subtracting 1 from both sides: 4p>-8; then we divide both sides by 4, obtaining p>-2 Draw an open circle at p=-2 and from this open circle draw an arrow to the right.
If 6p+3<33, 6p<30. Dividing both sides by 6, p<5. Draw an open circle at p=5 and from this open circle draw an arrow to the right.
Now determine the p values for which your two arrows coincide. The first arrow begins at p=-2 and extends to the right from there; the second arrow begins at p=5 and extends to the left. So, the only coincidence of the two arrows is between -2 and +5 (noting that the arrows do NOT touch p=-2 or p=5).
The solution set can be writtten as -2<p<5, or as (-2,5).
If 4p+1>-7, we solve for p by subtracting 1 from both sides: 4p>-8; then we divide both sides by 4, obtaining p>-2 Draw an open circle at p=-2 and from this open circle draw an arrow to the right.
If 6p+3<33, 6p<30. Dividing both sides by 6, p<5. Draw an open circle at p=5 and from this open circle draw an arrow to the right.
Now determine the p values for which your two arrows coincide. The first arrow begins at p=-2 and extends to the right from there; the second arrow begins at p=5 and extends to the left. So, the only coincidence of the two arrows is between -2 and +5 (noting that the arrows do NOT touch p=-2 or p=5).
The solution set can be writtten as -2<p<5, or as (-2,5).