Answer:
Standard form of the equation, [tex]3x^2+19x-14=0[/tex]
Factor of the equation is, [tex](x+7)(3x-2)=0[/tex]
Step-by-step explanation:
The standard form of the quadratic equation is given as
[tex]Ax^2+Bx+C = 0[/tex]
Given the equation:
[tex]3x^2+19x = 14[/tex]
Subtract 14 from both sides we have;
[tex]3x^2+19x-14=0[/tex]
⇒The standard form of the equation is, [tex]3x^2+19x-14=0[/tex]
Now, find the factor of the given equation:
[tex]3x^2+19x-14=0[/tex]
⇒[tex]3x^2+21x-2x-14=0[/tex]
⇒[tex]3x(x+7)-2(x+7) = 0[/tex]
⇒[tex](x+7)(3x-2)=0[/tex]
Therefore, the factor of the equation is, [tex](x+7)(3x-2)=0[/tex]
