Work out the a:b:c ratio.
b is present in both ratios, find first the LCM of 8 and 6, which is 24.
Multiply a:b=3:8 by 3 to get a:b=9:24
Similarly, multiply b:c=6:11 by 4 to get b:c=24:44
Then we conclude
a:b:c=9:24:44
Since there is no common factor among the three numbers, this is the simplest ratio possible.
If a,b and c are integers, the smallest values for a,b and c are 9,24,44.
Add up the three numbers to get the least value of a+b+c=77.
The smallest possible value of a+b+c is equal to 77 where a, b, and c are 9, 24, and 44 respectively and it can be determine by using arithmetic operations.
Given :
The following steps can be used to determine the value of (a+b+c) :
Step 1 - b present in both the ratios therefore first find the LCM of 6 and 8.
The LCM of 6 and 8 is 24.
Step 2 - Now, multiply numerator and denominator of ratio (1) by 3.
[tex]\rm \dfrac{a}{b}= \dfrac{3\times 3}{8\times 3}=\dfrac{9}{24}[/tex]
Step 3 - Now, multiply numerator and denominator of ratio (2) by 4.
[tex]\rm \dfrac{b}{c}= \dfrac{6\times 4}{11\times 4}=\dfrac{24}{44}[/tex]
For the smallest possible value of a+b+c the value of a, b, and c are 9, 24, and 44.
Therefore, the smallest possible value of a+b+c is equal to 9+24+44 = 77.
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https://brainly.com/question/15385899
