The margin of error for loggerhead sea turtle eggs to hatch in a simple random sample are normally distributed is 0.66.
Normally distributed data is the distribution of probability which is symmetric about the mean.
The mean of the data is the average value of the given data.
The standard deviation of the data is the half of the difference of the highest value and mean of the data set.
It is given in the problem that the total number of sample (n) is 35.
The mean value of the data is 50 days and the standard deviation (σ) is of 2 days. The confidence interval is of 95% equal to a z-score of 1.96.
Margin of error is the product of critical values and the standard deviation of error. The formula for the margin of error can be given as,
[tex]MOE=z\sqrt{\dfrac{\sigma^2}{n}}[/tex]
Put the values as,
[tex]MOE=1.96\sqrt{\dfrac{2^2}{35}}\\MOE=0.66\\[/tex]
Thus the margin of error for the population mean is 0.66. The option D is the correct option.
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