A battery delivering a current of 55.0 a to a circuit has a terminal voltage of 14.3 v. the electric power being dissipated by the internal resistance of the battery is 34 w. find the emf of the battery.
Let Vi be voltage drop of internal resistance. Then Vi•I=34W. Vi=34/55=0.618V. This is lost internally to the battery so the total voltage of the battery is 14.3V+0.618V=8.84V
