According to this diagram, what is tan 62 degrees ?

Answer:
[tex]tan62^{\circ}=1.875[/tex]
Step-by-step explanation:
We are given that
Perpendicular side of right triangle =15 units
Base of right triangle =8 units
Hypotenuse of right triangle=17 units
We have to find the value of [tex]tan62^{\circ}[/tex]
We know that
[tex]tan\theta=\frac{Perpendicular\;side}{Base}[/tex]
Substitute the values then we get
[tex]tan62^{\circ}=\frac{15}{8}=1.875[/tex]
Hence, the value of [tex]tan62^{\circ}=1.875[/tex]
According to this diagram, the tan 62 degrees, is the ratio of opposite side and the adjacent side of the triangle which is equal to 1.875 units.
In a right angle triangle ratio of opposite side to the adjacent side is equal the tangent angle between the adjacent side and hypotenuse side.
[tex]\tan \theta=\dfrac{b}{a}[/tex]
Here, (b) is the opposite side, (a) is the adjacent side, and [tex]\theta[/tex] is the angle made between adjacent side and hypotenuse side.
The sides of the triangle is 8, 15 and 17 units long and the measure of the angles of the right angle triangle is 62, 90 and 28 degrees.
Here in the given triangle the base is side which is 15 units long.Re draw the triangle as shown below.
In the attached triangle below, the opposite side of the triangle is 15 units and the adjacent side of the triangle is 8 units long.
The angle between the opposite side and adjacent side is 62 degrees. Thus using the right angle triangle property as,
[tex]\tan (62)=\dfrac{15}{8}\\\tan (62)=1.875[/tex]
Thus, according to this diagram, the tan 62 degrees, is the ratio of opposite side and the adjacent side of the triangle which is equal to 1.875 units.
Learn more about the right angle triangle property here;
https://brainly.com/question/22790996