Answer: Solution is,
d. (2, 0)
Step-by-step explanation:
Since, the equation of line that passes through points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is,
[tex](y-y_1)=\frac{x_2-x_1}{y_2-y_1}(y-y_1)[/tex]
Thus, the equation of line through the points (3, 1) and (–5, –7) is,
[tex](y-1)=\frac{-7-1}{-5-3}(x-3)[/tex]
[tex](y-1)=\frac{-8}{-8}(x-3)[/tex]
[tex]y - 1 = x - 3[/tex]
[tex]\implies y = x - 2------(1)[/tex],
Equation of second line is,
[tex]y = 0.5x - 1 -----(2)[/tex],
By equation (1) and (2),
x - 2 = 0.5x - 1 ⇒ 0.5x = 1 ⇒ x = 2,
From equation (1),
We get, y = 0,
Hence, the solution of line (1) and (2) is (2,0).
