Answer is: X = Al₂(SO₄)₃; Y = H₂O.
Balanced chemical reaction:
2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O.
Al(OH)₃ is aluminium hydroxide.
H₂SO₄ is sulfuric acid.
Al₂(SO₄)₃ is salt aluminium sulfate. Aluminium has oxidation number +3 and sulfate has charge -2.
H₂O is water.
Acids and bases when react (neutralisation) produce salt and water.
The value of X and Y in the equation is:
A. The value of X is Al₂(SO₄)₃
B. The value of Y is H₂O
Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The reactants are located on the left side while the products are located on the right side.
Reactants —> Products
To determine the value of X and Y, we shall write the balanced equation for the reaction. This is given below:
2Al(OH)₃ + 3H₂SO₄ → X + 6Y
Al(OH)₃ + H₂SO₄ → Al₂(SO₄)₃ + H₂O
There are 2 atoms of Al on the right side and 1 atom on the left. It can be balanced by writing 2 before Al(OH)₃ as shown below:
2Al(OH)₃ + H₂SO₄ → Al₂(SO₄)₃ + H₂O
There are a total of 8 atoms of H on the left side and 2 atoms on the right side. It can be balanced by writing 3 before H₂SO₄ and 6 before H₂O as shown below:
2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O
Now, the equation is balanced.
Comparing the above balance equation with:
2Al(OH)₃ + 3H₂SO₄ → X + 6Y
The value of X and Y is:
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