Respuesta :
What we are going to do with this problem is combine all the like terms.
so to begin, we notice that there are two numbers with a^2 involved, and two numbers with an a.
thus:
8[tex] a^{2} [/tex]+(-3[tex] a^{2} [/tex] is going to equal 5[tex] a^{2} [/tex] because adding a negative is just like subtracting.
then we move on to (6a)-(2a) giving us 4a
5 is the only term that stays the same because there are no other similar terms.
last but not least, put the equation together!
answer: 5[tex] a^{2} [/tex]+4a+5
so to begin, we notice that there are two numbers with a^2 involved, and two numbers with an a.
thus:
8[tex] a^{2} [/tex]+(-3[tex] a^{2} [/tex] is going to equal 5[tex] a^{2} [/tex] because adding a negative is just like subtracting.
then we move on to (6a)-(2a) giving us 4a
5 is the only term that stays the same because there are no other similar terms.
last but not least, put the equation together!
answer: 5[tex] a^{2} [/tex]+4a+5
(8a^2 + 6a + 5) + (-3a^2 -2a)
5a^2 + 4a + 5 <------------ answer
5a^2 + 4a + 5 <------------ answer