rebecca101
contestada

PLEASE HELP!!!
How can one thirdx − 2 = one fourthx + 11 be set up as a system of equations?

3y − x = −6
4y − x = 44

3y + x = −6
4y + x = 44

3y − 3x = −6
4y − 4x = 44

3y + 3x = −6
4y + 4x = 44

Respuesta :

texaschic101
1/3x - 2 = 1/4x + 11....it looks to me like one y was subbed in for another...

ur 2 equations are :
y = 1/3x - 2 and y = 1/4x + 11...but we need them in standard form...

y = 1/3x - 2
-1/3x + y = -2 ..multiply by 3
-x + 3y = -6.....or 3y - x = -6 <==

y = 1/4x + 11
-1/4x + y = 11 ...multiply by 4
-x + 4y = 44 or 4y - x = 44 <==

Answer: 3y-x=-6 4y-x=44

Step-by-step explanation: okay so when I was taking the test the first answer was really confusing so here is simple answer. Also its correct, your welcome

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