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Suppose you throw a ball vertically downward with a speed of 10 m/s. neglecting air friction, what would be the speed of the ball one second later?

Respuesta :

brockminton
The speed of the ball would be 19.8 m/s

Answer:

The speed of the ball one second later is 19.8 m/s.

Explanation:

Given that,

Initial speed of the ball, u = 10 m/s

Let v is the speed of the ball after one second. The ball will move downward under the action of gravity, a = g

Using the first equation of motion as :

[tex]v=u+at[/tex]

[tex]v=u+gt[/tex]

[tex]v=10+9.8\times 1[/tex]

v = 19.8 m/s

So, the speed of the ball one second later is 19.8 m/s. Hence, this is the required solution.

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