sashaarcaya
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Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?
4x + 8
2x + 12
x^2 − 4
x^2 − 16

Respuesta :

x^2-4 will be the answer ..

as denominator must not be zero to get a valid answer.

hope it helps

Answer:

[tex]x^2-4[/tex]

Step-by-step explanation:

Sally found that a solution of x = 2 was extraneous for her function.

Extraneous solution is a solution that makes the denominator 0

Possible denominator are given . LEts plug in 2 for x and check which option gives us 0

[tex]4x+8=4(2)+8= 16[/tex]  

[tex]2x+12=2(2)+12=4+12= 16[/tex]

[tex]x^2-4= (2)^2-4= 4-4=0[/tex]

[tex]x^2-16= (2)^2-16= 4-16= 12[/tex]

[tex]x^2-4[/tex] gives us 0 when we plug in 2 for x.

So x=2 was extraneous solution for [tex]x^2-4[/tex]

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