A solution contains 0.10 m sodium cyanide and 0.10 m potassium hydroxide. solid zinc acetate is added slowly to this mixture. what is the formula of the substance that precipitates first?

1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)

Ksp{Zn(OH)₂}=1.2*10⁻¹⁷

2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)

Ksp{Zn(CN)₂}=2.6*10⁻¹³

Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}

Zn(OH)₂ precipitates first

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mickymike92 mickymike92 · Answer 2 · 2022-04-20T13:17:28+02:00

From the solubility products of the solutes produced, the Ksp of {Zn(OH)₂ is less than the Ksp of Zn(C_N)₂, Zn(OH)₂ precipitates first.

What is solubility product? Ksp of a solute?

The solubility product, Ksp of a solute is the product of the ions produced when a solute dissociates into ions when dissolved in a solvent.

The higher the Ksp of a solute, the more soluble it is ain a solvent.

The equation of the reaction of zinc acetate with each of the solutions as well their solubility products is given below:

[tex] Zn(CH₃COO)₂(s) + 2KOH(aq) \rightarrow Zn(OH)₂(s) + 2CH₃COOK(aq) \\ [/tex]

[tex]Ksp \: {Zn(OH)₂}=1.2*10^{-17}[/tex]

[tex]Zn(CH₃COO)₂(s) + 2NaC \: N(aq) \rightarrow Zn(C \: N)₂(s) + 2CH₃COONa(aq) \\ [/tex]

[tex]Ksp \: {Zn(C \: N)₂}=2.6*10^{-13}[/tex]

Therefore, since the Ksp of Zn(OH)₂ is less than the Ksp of Zn(C_N)₂, Zn(OH)₂ precipitates first.

Learn more about solubility product at: https://brainly.com/question/23946616