This is an example of combustion reaction, a substance is reacted with oxygen to form products. The balanced reaction for the burning of FeS2 is:
2 FeS2 + 5.5 O2 ---> 4 SO2 + Fe2O3
Therefore based on stoichiometric ratio of the reaction, for every 2 moles of FeS2, 4 moles of SO2 is produced.
First, lets calculate for the number of moles of FeS2 supplied: (molar mass of FeS2 = 119.965 g/mol)
n FeS2 = 202.33 g / (119.965 g/mol)
n FeS2 = 1.6866 mol
Calculate for the number of moles of SO2 produced using the ratio:
n SO2 = 1.6866 mol (4 / 2) = 3.373 mol SO2
Converting to mass: (molar mass SO2 = 64.066 g/mol)
m SO2 = 3.373 mol * 64.066 g/mol
m SO2 = 216.10 g (ANSWER)