Answer: The mass of carbon dioxide produced is 46.7 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of hexane = 15.6
Molar mass of hexane = 88.2 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of hexane}=\frac{15.6g}{88.2g/mol}=0.177mol[/tex]
The chemical equation for the combustion of hexane follows:
[tex]2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O[/tex]
As, oxygen gas is present in excess, it is considered as an excess reagent.
Thus, hexane is considered as a limiting reagent because it limits the formation of product
By Stoichiometry of the reaction:
2 moles of hexane produces 12 moles of carbon dioxide
So, 0.177 moles of hexane will produce = [tex]\frac{12}{2}\times 0.177=1.062mol[/tex] of carbon dioxide
Now, calculating the mass of carbon dioxide by using equation 1:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 1.062 moles
Putting values in equation 1, we get:
[tex]1.062mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.062mol\times 44g/mol)=46.7g[/tex]
Hence, the mass of carbon dioxide produced is 46.7 grams.
