Respuesta :
8x^2-2x-1=0
8x^2-4x+2x-1=0
4x(2x-1)+1(2x-1)=0
(4x+1)(2x-1)=0
x=1/2 and -1/4
So the sum is 1/2-1/4=1/4
1/4
8x^2-4x+2x-1=0
4x(2x-1)+1(2x-1)=0
(4x+1)(2x-1)=0
x=1/2 and -1/4
So the sum is 1/2-1/4=1/4
1/4
8x^2 - 2x = 1
8x^2 - 2x - 1 = 0
(2 +/-√(-2)^2 - 4(8)(-1))/ 2(8)
(2 +/-√4 + 32) / 16
(2 +/-√36) / 16
(2 +/- 6) / 16
2+6/16
1/2
2-6/16
-1/4
now since they want the sum of the roots
1/2 - 1/4
sum = 1/4
8x^2 - 2x - 1 = 0
(2 +/-√(-2)^2 - 4(8)(-1))/ 2(8)
(2 +/-√4 + 32) / 16
(2 +/-√36) / 16
(2 +/- 6) / 16
2+6/16
1/2
2-6/16
-1/4
now since they want the sum of the roots
1/2 - 1/4
sum = 1/4