Respuesta :
[tex]4x^2 + 23x- 6 = \\ 4x^2 +24x - x-6=\\4x(x+6)-(x+6)=\\(x+6)(4x-1)[/tex]
The factors of 4x^2 + 23x − 6 are (4x-1)and (x+6).
We have given that,
[tex]4x^2 + 23x - 6[/tex]
We have to determine the factors of given expression
What is the quadratic formula?
[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4\cdot \:a\left(c\right)}}{2\cdot \:a}[/tex]
[tex]x_{1,\:2}=\frac{-23\pm \sqrt{23^2-4\cdot \:4\left(-6\right)}}{2\cdot \:4}[/tex]
[tex]x_{1,\:2}=\frac{-23\pm \:25}{2\cdot \:4}[/tex]
[tex]x_1=\frac{-23+25}{2\cdot \:4},\:x_2=\frac{-23-25}{2\cdot \:4}[/tex]
[tex]=\frac{-23+25}{2\cdot \:4}[/tex]
[tex]=\frac{2}{2\cdot \:4}[/tex]
[tex]=\frac{1}{4}[/tex]
[tex]x=\frac{1}{4},\:x=-6[/tex]
Therefore the factors are(4x-1)and (x+6)
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