The polygon which has an interior angle sum of 1080° is an Octagon
From the question, we are to determine which polygon has an interior angle sum of 1080°
To find that, we will determine the number of sides the polygon has.
From the formula for sum of the interior angles in a polygon
Sum of interior angles = (n-2)180°
Where n is the number of sides
Then,
1080° = (n-2) 180°
1080° ÷ 180° = n-2
6 = n-2
n = 6 + 2
n = 8
A polygon with 8 sides is called an Octagon
Hence, the polygon which has an interior angle sum of 1080° is an Octagon
Learn more on Interior angles of a Polygon here: https://brainly.com/question/1502196
