The given function [tex]f(x) = \dfrac{ 3}{x + 2} -\sqrt{x-3}[/tex] The value of f(7) would be -1.67.
The function is a type of relation, or rule, that maps one input to a specific single output.
The given function
[tex]f(x) = \dfrac{ 3}{x + 2} -\sqrt{x-3}[/tex]
By substitute x = 7 to find f(7)
[tex]f(7) = \dfrac{ 3}{7 + 2} -\sqrt{7-3}\\\\f(7) = \dfrac{ 3}{9} -\sqrt{4}\\\\f(7) = \dfrac{ 1}{3} -2\\\\f(7) = \dfrac{ 1 - 6}{3}\\\\f(7) = \dfrac{ -5}{3}\\[/tex]
f(7)= -5/3 = -1.67
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