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A ball is thrown directly downward with an initial W speed of 8.00 m/s from a height of 30.0 m. After what time interval does it strike the ground?

Respuesta :

Vf^2=Vi^2+2ad
Vf^2=64+2(9.8)(30)
Vf^2=652
Vf=25.5

Now use Vf=Vi+at

25.5=8+2(9.8)t
solve for t
t=1.789 s

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