The coordinates of the points of intersections of [tex]l[/tex] and the curve are [tex](x_{1}, y_{1}) = (4,3)[/tex] and [tex](x_{2}, y_{2}) = (1.5, 8)[/tex].
According to the statement, we get the following nonlinear system of equations:
[tex]x\cdot y = 12[/tex] (1)
[tex]2\cdot x + y = 11[/tex] (2)
Now we proceed to solve for each variable by algebraic means. By (1):
[tex]y = \frac{12}{x}[/tex]
Then we apply the formula in (2):
[tex]2\cdot x + \frac{12}{x} = 11[/tex]
[tex]2\cdot x^{2}+12 = 11\cdot x[/tex]
[tex]2\cdot x^{2}-11\cdot x +12 = 0[/tex]
Roots are found by the quadratic formula and (1):
[tex]x_{1} = 4[/tex], [tex]y_{1} = 3[/tex]
[tex]x_{2} = 1.5[/tex], [tex]y_{2} = 8[/tex]
The coordinates of the points of intersections of [tex]l[/tex] and the curve are [tex](x_{1}, y_{1}) = (4,3)[/tex] and [tex](x_{2}, y_{2}) = (1.5, 8)[/tex].
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