Respuesta :

irspow
Without calculus...

y=5x^2-20x+1357

y-1357=5x^2-20x

(y-1357)/5=x^2-4x

(y-1357)/5+4=x^2-4x+4

(y-1357)/5+4=(x-2)^2

(y-1357)/5=(x-2)^2-4

y-1357=5(x-2)^2-20

y=5(x-2)^2+1337

So the minimum value for y is 1337

With calculus...

y=5x^2-20x+1357

dy/dx=10x-20

dy/dx=0 when

10x-20=0

10x=20

x=2

y(2)=5(4)-20(2)+1357=1337

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