well, for the current price today, let's see, not even one day has passed, to we don't have a "t" value that's greater than 0, so since today 0years and 0days and 0seconds have passed, t =0
[tex]\bf p(t)=400(1.037)^0\implies p(t)=400\cdot 1\implies \boxed{p(t)=400}[/tex]
now, 8 years from now, well, 8 years would had passed by then, t = 8
[tex]\bf p(t)=400(1.037)^8\implies p(t)\approx 400\cdot 1.3373037\implies \boxed{p(t)\approx 535}[/tex]
