Answer:
After the 4 second arrow is released, it will hit the ground.
Step-by-step explanation:
Consider the provided formula.
[tex]h(t)=64t-16t^2[/tex]
We need to find how long after the arrow is released does it hit the ground.
If the arrow hit the ground that means the value of h(t)=0.
Substitute the value of h(t)=0 and solve the equation as shown.
[tex]64t-16t^2=0[/tex]
[tex]16t(4-t)=0[/tex]
Now use zero product rule: If ab=0 then either a=0 or b=0
[tex]16t=0\ or\ 4-t=0[/tex]
[tex]t=0\ or\ -t=-4[/tex]
[tex]t=0\ or\ t=4[/tex]
Hence, after the 4 second arrow is released, it will hit the ground.
