For the first one use the slope formula: [tex]m= \frac{ y_{2}- y_{1} }{ x_{2}- x_{1} } [/tex]
So for you that would look like this: [tex]m= \frac{-4+1}{-2-7}= \frac{-3}{-9}= \frac{1}{3} [/tex]
For number 2, in order for a slope to be 0, it has to be a completely horizontal line with no steepness whatsoever. That can ONLY happen with lines that are "y=some constant with no x". So that answer has to be y = -5. For that last one, we have to use the slope-intercept form of a line and use the point they give us along with the slope to find the y-intercept, or the "b". That looks like this for us: [tex] \frac{5}{6}=1(0)+b [/tex] so b= 5/6. So our equation, fitting the slope and y intercept back in, gives us [tex]y=x+ \frac{5}{6} [/tex]
