Answer: 55.35ml
Explanation:
[tex]Ca+2HF\rightarrow CaF_2+H_2[/tex]
To calculate the given moles, we use the formula:
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]Moles=\frac{85.8g}{78g/mol}=1.1moles[/tex]
By stoichiometry of the reaction,
1 mole of [tex]CaF_2[/tex] is produced by 1 mole of Ca
1.1 moles of [tex]CaF_2[/tex] are produced by=[tex]\frac{1}{1}\times 1.1=1.1 moles[/tex] of Ca.
Mass of [tex]CaF_2=\text{no of moles}\times \text{Molar mass}[/tex]
Mass of [tex]CaF_2=1.1\times {78}=85.8g[/tex]
[tex]Volume=\frac{Mass}{Density}[/tex]
[tex]Volume=\frac{85.8g}{1.55g/ml}=55.35ml[/tex]
