Respuesta :
The changing rate of the amount of water in the watering can is a constant rate of 0.15 gallon per minute.
The initial volume of water in the can at time = 0 is 5 gallons
The function will be a linear function in the form of [tex]y=ax+b[/tex] where
[tex]y[/tex] is the volume of water in the can after [tex]x[/tex] minutes
[tex]a[/tex] is the changing rate
[tex]b[/tex] is the initial volume when time is 0
Substitute all the values into the form we have
[tex]y=0.15x+5[/tex]
The initial volume of water in the can at time = 0 is 5 gallons
The function will be a linear function in the form of [tex]y=ax+b[/tex] where
[tex]y[/tex] is the volume of water in the can after [tex]x[/tex] minutes
[tex]a[/tex] is the changing rate
[tex]b[/tex] is the initial volume when time is 0
Substitute all the values into the form we have
[tex]y=0.15x+5[/tex]
Answer:
The changing rate of the amount of water in the watering can is a constant rate of 0.15 gallon per minute.
The initial volume of water in the can at time = 0 is 5 gallons
The function will be a linear function in the form of where
is the volume of water in the can after minutes
is the changing rate
is the initial volume when time is 0
Substitute all the values into the form we have
Step-by-step explanation:
y=0.15x +5