Respuesta :
[tex]\sqrt{32}+\sqrt{2}=\sqrt{16\times 2}+\sqrt{2}=\sqrt{16}\times \sqrt{2}+\sqrt{2}=4\sqrt{2}+\sqrt{2}=\boxed{5\sqrt{2}}[/tex]
The answer is "It is irrational and equal to 5 multiplied by square root of 2."
The answer is "It is irrational and equal to 5 multiplied by square root of 2."
Answer:
It is irrational and equal to [tex]5[/tex] multiplied by square root of [tex]2[/tex]
Step-by-step explanation:
we have
[tex]\sqrt{32}+\sqrt{2}[/tex]
Remember that
[tex]32=2^{5}[/tex]
substitute in the expression
[tex]\sqrt{2^{5}}+\sqrt{2}=4\sqrt{2}+\sqrt{2}=5\sqrt{2}[/tex]
therefore
It is irrational and equal to [tex]5[/tex] multiplied by square root of [tex]2[/tex]