h = 11 m, the vertical distance that the bullet falls.
Initial vertical velocity = 0
Horizontal velocity = 144.7 m/s
The time, t, taken to fall 11 m is given by
(1/2)*(9.8 m/s²)*(t s)² = (11 m)
4.9t² = 11
t = 1.4983 s
If aerodynamic resistance is ignored, the horizontal distance traveled before the bullet hits the ground is
d = (144.7 m/s)*(1.4983 s) = 216.8 m
Answer: 216.8 m
