kidkash773CA
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Consider the potassium permanganate reaction again.

2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2

How many moles of water are produced when 3.45 moles of KMnO4 react? Give your answer to the nearest 0.1 moles.

I know the answer is 13.8 moles but I dont know how to find this. Please explain.

Respuesta :

Willchemistry
Hey there !

Mole ratio :

2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

2 moles KMnO4 ----------------- 8 moles H2O
3.45 moles KMnO4 ------------- (moles H2O )

Moles H2O = 3.45 * 8 / 2

Moles H2O = 27.6 / 2

 = 13.8 moles of H2O

The option that was given is wrong , You're right.

Answer:

Moles of H2O produced = 13.8

Explanation:

Given:

Moles of KMnO4 reacted = 3.45

To determine:

moles of H2O produced

Explanation:

Given reaction:

2KMnO4 + 16HCl →2KCl + 2MnCl2 + 8H2O + 5Cl2

Based on the reaction stoichiometry:

2 moles of KMnO4 produces 8 moles of H2O

Therefore, moles of H2O produced when 3.45 moles of KMnO4 react is:

[tex]= \frac{3.45\ moles\ KMnO4 * 8\ moles\ H2O}{2\ moles\ KMnO4} = 13.8[/tex]

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