Assume that the incline is frictionless.
Refer to the diagram shown below.
Note that 75 cm = 0.75 m.
Therefore the angle of the incline is given by
sin(x) = 0.75/2.3 = 0.3261.
The weight pushed up the incline is W = 5501 N.
The component of the weight acting down the incline is
W*sin(x) = 5501*0.3261 = 1793.9 N
The force, F, should overcome this weight acting along the incline, therefore
F = 1794 N (nearest integer)
Answer: 1794 N
