Respuesta :
Answer: The equation of the ellipse is
[tex]\dfrac{x^2}{169}+\dfrac{y^2}{25}=1.[/tex]
Step-by-step explanation: We are given to find the equation of an ellipse that has a center at the origin, a vertex along the major axis at (13, 0) and a focus at (12, 0).
Since the focus lies on the X-axis, so the standard equation of an ellipse with major axis as X-axis is given by
[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
According to given information, we have
a vertex along the major axis, (a, 0) = (13, 0)
⇒ length of the major axis, a = 13,
co-ordinates of focus, (c, 0) = (12, 0)
⇒ c = 12.
We know that
[tex]c^2=a^2-b^2.[/tex]
Therefore,
[tex]12^2=13^2-b^2\\\\\Rightarrow 144=169-b^2\\\\\Rightarrow b^2=169-144\\\\\Rightarrow b^2=25\\\\\Rightarrow b=5.[/tex]
Thus, from equation (i), we get
[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\\\Rightarrow \dfrac{x^2}{13^2}+\dfrac{y^2}{5^2}=1\\\\\\\Rightarrow \dfrac{x^2}{169}+\dfrac{y^2}{25}=1.[/tex]
The equation of the ellipse is
[tex]\dfrac{x^2}{169}+\dfrac{y^2}{25}=1.[/tex]
The equation of the ellipse along the major axis at (13, 0), and a focus at (12, 0) is; x²/169 + y²/25 = 1
Equation of an ellipse
The equation of an ellipse whose center is the origin, (0,0) usually takes the form;
- x²/a² + y²/b² = 1
The coordinates of the vertex on the major axis is given as; (13,0) and the focus at (12,0)
Hence, the square of the length of the minor axis;
- b² = a² - c²
- b² = 169 - 144
- b² = 25.
Hence, the equation of the described ellipse is;
- x²/169 + y²/25 = 1
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