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Can somebody solve this??
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Activity 7: Derive My Equation!

Work in pairs.

A. Determine the equation of the quadratic function represented by the table of values below.

x: -4 -3 -2 -1 0 1
y: -20 -13 -8 -5 -4 -5

B. The vertex of the parabola is (-3, 5) and it is the minimum point of the graph. If the graph passes though the point (-2, 7), what is the equation of the quadratic function?

C. Observe the pattern below and draw the 4th and 5th figures.

Make a table of values for the number of squares at the bottom and the total number of unit squares.

What is the resulting equation of the function?

Can somebody solve this please answer respectfully Activity 7 Derive My Equation Work in pairs A Determine the equation of the quadratic function represented by class=

Respuesta :

sqdancefan

Answer:

 A.  y = -x² -4

  B.  y = 2(x +3)² +5

Step-by-step explanation:

You want the equations for the quadratic functions with the given parameters and table of values.

A. Table

The table shows the y-value is a maximum at x = 0. It also shows the y-value is 1 unit lower when x = ±1, one unit away from the vertex. That "1 unit lower" tells you the vertical scale factor is a=-1.

The formula for the quadratic function with vertex (h, k) and vertical scale factor 'a' is ...

  y = a(x -h)² +k

Here, we have (h, k) = (0, -4) and a = -1, so our function equation is ...

  y = -x² -4

B. Vertex

We notice the point (-2, 7) is 1 unit horizontally from the vertex at (-3, 5), and is 2 units up. This means our vertical scale factor is +2, so the equation is .,..

  y = 2(x +3)² +5

C. Square pattern

No patterns are shown.

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