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Your goal is to do the steps you did in the
previous section, but in reverse. Your goal is to
do the steps you did in the previous section,
but in reverse:
• You know the mass of the Na₂CO,
product: 4.08g
• The molar mass of Na₂CO, is 105.99
g/mol, so you can find the moles of
Naâ‚‚CO, produced.
. Using the balanced chemical equation you
can find the moles of NaHCO,
• The molar mass of NaHCO, is 84.01
g/mol, so you can find the mass of
NaHCO,.
How can you use this information to find the
mass of the initial amount of NaHCO,?

Respuesta :

craftman1

Explanation:

To find the mass of the initial amount of NaHCO₃, you can work backward through the steps provided. Here's the reverse process:

1. **Find Moles of NaHCO₃ Produced:**

- Given mass of Na₂CO₃ product: 4.08 g

- Molar mass of Na₂CO₃: 105.99 g/mol

- Calculate moles of Na₂CO₃ produced: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \)

2. **Use Balanced Chemical Equation:**

- Utilize the balanced chemical equation to relate moles of Na₂CO₃ to moles of NaHCO₃.

- If the balanced equation is \( a \, \text{NaHCO}_3 + b \, \text{NaOH} \rightarrow c \, \text{H}_2\text{O} + d \, \text{CO}_2 \), then the ratio of moles is \( a : c \).

3. **Find Moles of NaHCO₃:**

- Use the ratio obtained from the balanced equation to find moles of NaHCO₃ produced.

4. **Find Mass of NaHCO₃:**

- Molar mass of NaHCO₃: 84.01 g/mol

- Calculate the mass of NaHCO₃ produced: \( \text{mass} = \text{moles} \times \text{molar mass} \)

5. **Determine Initial Mass of NaHCO₃:**

- Since this is a chemical reaction, the initial amount of NaHCO₃ is equal to the mass of NaHCO₃ produced.

So, by working backward through these steps, you can determine the initial mass of NaHCO₃ based on the given information.

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