Answer:
-5
Step-by-step explanation:
First of all, way to go in making people help you with solutions by using threats of being reported.
Anyways. Your expression can be rewritten using some simple changes. First we split up the numerator into two parts where the later is divisible by the denominator and the former can be factored by the denominator. The rest is trivial.
[tex]\frac{2x^{2} - x - 3}{x+1} = \frac{(2x^{2} -2) - x-1)}{x+1} = \frac{(2x^{2} -2) - (x+1)}{x+1} = \frac{2*(x^{2} -1) - (x+1)}{x+1} =\frac{2*(x-1)*(x+1) - (x+1)}{x+1} = \frac{(x+1)* (2*(x-1)-1)}{x+1} =\frac{(x+1)* (2x-3)}{x+1} = 2x-3[/tex]
With [tex]x \rightarrow -1 \implies 2x-3 \rightarrow -5[/tex]
