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A sinusoidal wave of frequency f = 250 Hz has a speed v = 1000 m/s. Calculate the phase difference (in radians) between two points on the wave that are separated by a distance of 1.00 m.
o 1.57
o 3.14
o 0
o 2.36
o 6.28

Respuesta :

Answer:

1.57 rad

Explanation:

Given:

frequency (f) = 250 Hz

speed (v) = 1000 m/s

distance (Δx) = 1.00 m

[tex]\boxed{wave\ length\ (\lambda)=\frac{v}{f} }[/tex]

[tex]\lambda=\frac{1000}{250}[/tex]

  [tex]=4\ m[/tex]

[tex]\boxed{phase\ difference\ (\Delta\phi)=\frac{\Delta x}{\lambda} \times2\pi}[/tex]

[tex]\Delta\phi=\frac{1}{4} \times2\pi[/tex]

     [tex]=\frac{\pi}{2}[/tex]

     [tex]=\frac{3.14}{2}[/tex]

     [tex]=1.57\ rad[/tex]

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