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The roadside vegetable stand sells pumpkins for five dollars each and squashes for three dollars each one day they sold six more squash than pumpkins and their sales total $98 right and solve a system of equations to find how many pumpkins and squash they sold

Respuesta :

Meherpuya

Answer:

Let's denote the number of pumpkins as \( P \) and the number of squashes as \( S \).

From the given information, we have two equations:

1. The number of squashes sold is six more than the number of pumpkins: \( S = P + 6 \).

2. The total sales amount is $98: \( 5P + 3S = 98 \).

Now, substitute the expression for \( S \) from the first equation into the second equation:

\[ 5P + 3(P + 6) = 98 \]

Simplify and solve for \( P \).

After finding the value for \( P \), substitute it back into the equation \( S = P + 6 \) to find \( S \).

This will give you the number of pumpkins and squashes they sold.

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