Respuesta :
To find the equation of the line passing through the points (-4, 5) and (2, -4), we can use the point-slope form of a linear equation.
The point-slope form is given by:
y - y1 = m(x - x1)
where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.
First, let's calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates (-4, 5) and (2, -4), we have:
m = (-4 - 5) / (2 - (-4))
= -9 / 6
= -3/2
Now, we can choose one of the points, let's use (-4, 5), and substitute the values into the point-slope form equation:
y - y1 = m(x - x1)
y - 5 = (-3/2)(x - (-4))
y - 5 = (-3/2)(x + 4)
y - 5 = (-3/2)x - 6
y = (-3/2)x - 1
Therefore, the equation of the line passing through the points (-4, 5) and (2, -4) is y = (-3/2)x - 1.
The point-slope form is given by:
y - y1 = m(x - x1)
where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.
First, let's calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates (-4, 5) and (2, -4), we have:
m = (-4 - 5) / (2 - (-4))
= -9 / 6
= -3/2
Now, we can choose one of the points, let's use (-4, 5), and substitute the values into the point-slope form equation:
y - y1 = m(x - x1)
y - 5 = (-3/2)(x - (-4))
y - 5 = (-3/2)(x + 4)
y - 5 = (-3/2)x - 6
y = (-3/2)x - 1
Therefore, the equation of the line passing through the points (-4, 5) and (2, -4) is y = (-3/2)x - 1.
