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Answer:
How to solve Related to Newton's law of universal gravitation in Physics I need this urgently please!!!
Mass 1 (327 kg) and mass 2 (25 4kg) are 68.1 m apart what is the gravitational force between them F=[]*10^[]NSolve ForKnown 1 Identify knowns & unknowns This question is asking to find force with knowns of mass of object 1, mass of object 2, and distance between centers of the masses. 2 Identify the related formula This is the formula used for problems related to Newton's law of universal gravitation.
Explanation:
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Answer:
[tex]1.2 \times 10^{-9} \, \textsf{N}[/tex]
Explanation:
To calculate the gravitational force between two masses, we can use Newton's Law of Universal Gravitation, which states:
[tex]\Large\boxed{\boxed{ F = \dfrac{{G \times m_1 \times m_2}}{{r^2}} }}[/tex]
where:
- [tex] F [/tex] is the gravitational force,
- [tex] G [/tex] is the gravitational constant ([tex]6.674 \times 10^{-11} \, \textsf{N} \cdot \textsf{m}^2/\textsf{kg}^2[/tex]),
- [tex] m_1 [/tex] and [tex] m_2 [/tex] are the masses,
- [tex] r [/tex] is the distance between the centers of the masses.
Given:
- [tex] m_1 = 327 \, \textsf{kg} [/tex]
- [tex] m_2 = 254 \, \textsf{kg} [/tex]
- [tex] r = 68.1 \, \textsf{m} [/tex]
Substitute the given values into the formula:
[tex] F = \dfrac{{(6.674 \times 10^{-11} \, \textsf{N} \cdot \textsf{m}^2/\textsf{kg}^2) \times (327 \, \textsf{kg}) \times (254 \, \textsf{kg})}}{{(68.1 \, \textsf{m})^2}} [/tex]
Now, compute the result:
[tex] F = \dfrac{{(6.674 \times 10^{-11} \times 327 \times 254)}}{{68.1^2}} [/tex]
[tex] F \approx \dfrac{{554329.092 \times 10^{-11}}}{{4637.61}} [/tex]
[tex] F \approx 119.5290445 \times 10^{-11} \, \textsf{N} [/tex]
[tex] F \approx 1.195290445 \times 10^{-9} [/tex]
[tex] F \approx 1.2 \times 10^{-9} [/tex]
Therefore, the gravitational force between the two masses is approximately :
[tex] \Large\boxed{\boxed{1.2 \times 10^{-9} \, \textsf{N}}}[/tex].
