Answer:
[tex](x+3)^2-5[/tex]
Step-by-step explanation:
Given is a quadratic equation as
[tex]x^2+6x+4[/tex]
To complete the square we have to suitably add and subtract a term depending on the coefficient of x.
Here coefficient of x =6 and coefficient of x square =1
Hence we have to add (6/2)^2=9 to make it a perfect square
[tex]x^2+6x+4\\x^2+6x+9-5\\=(x+3)^2-5[/tex]
Now we completed the square and made it in vertex form
Vertex is (-3,-5)
and
[tex]f(x) =(x+3)^2-5[/tex]
