Answer:
168 m
Explanation:
First of all we need to rememeber the formula to calculate the distance with the acceleration:
[tex]s= Vi*t+(\frac{1}{2}Vft^{2} )[/tex]
Now as we do not have time, we have to use first the formula for acceleration but cleared for time:
[tex]a=\frac{Vf-Vi}{t}[/tex]
We clear time and are left with:
[tex]t=\frac{Vf-Vi}{a}[/tex]
Now we insert the values we know:
[tex]t=\frac{Vf-Vi}{a}[/tex]
[tex]t=\frac{18-6}{3}[/tex]
[tex]t=\frac{12}{3}[/tex]
[tex]t=4[/tex]
Now that we have time we just have to insert the values into the first formula:
[tex]s= Vi*t+(\frac{1}{2}Vft^{2} )[/tex]
[tex]s= 6*4+(\frac{1}{2}(18)4^{2} )[/tex]
[tex]s= 24+(\frac{1}{2}(18)16 )[/tex]
[tex]s= 24+(144)[/tex]
[tex]s= 168m[/tex]
And the distance that he traveled while accelerating is 168m.
