If a sample of coke is 95% carbon by mass, determine the mass of coke needed to react with 1.0 ton of copper (II) oxide.. 2CuO(s)+C(s)---->2Cu(s)+CO2(g)

So thus far I have:
1 ton CuO = 907,185g CuO
907,185g CuO * (1mol CuO/79.545g CuO) = 11404 mols CuO (Rounded) [11404.676]
11404 mols CuO * (1 mol C/2 mol CuO) = 5702 mols C (Not Rounded - No Need)
5702 mols C * (12.0108g C/1 mol C) = 68485g C (Rounded) [68485.5816]
68485g C * 0.95 = >>65060.75g C<< (not rounded -exact)
[Should I not have rounded?]
Here's what someone else gave me...

1.0 ton x (2000 lb / 1 ton) x (1 kg / 2.2 lb) x (1000 g / 1 kg) = 9.09x10^5 g CuO

9.09x10^5 g CuO x (1 mol CuO / 79.5 g CuO) x (1 mol C / 2 mol CuO) x (12g C / 1 mol C) x (1 g coke / 0.95 g C) = 7.2x10^4 g coke .... to two significant digits

The difference being that he used scientific notation for the 1 ton in grams...

Which is correct?

Respuesta :

Actually, that is not the only difference between the two answers you have provided. The difference between the values of ton is negligible; however, the primary difference lies in the fact that you multiplied by 0.95 to accommodate for the percentage carbon in the first answer, while in the second answer it is being divided.

The second answer is correct because it is stated that the coke contains 95% carbon. This means that if 100 grams of coke are present, 95 grams are carbon. Because in your calculations you calculated the mass of carbon required, you must divide by 0.95 to find out the mass of coke required.