Respuesta :

[tex]( \frac{x^2 - x -12}{2x} ) [/tex] ÷ [tex]( \frac{x^2 - 2x - 8}{4x^2} )[/tex]

= [tex]( \frac{x^2 - x -12}{2x} ) [/tex] × [tex]( \frac{4x^2}{x^2 - 2x - 8} )[/tex]

= [tex] \frac{x(x^2 - x -12)}{x^2 - 2x - 8} [/tex]

= [tex] \frac{x(x^2 -4x +3x -12)}{x^2 -4x +2x -8} [/tex]

= [tex] \frac{x[x(x - 4) +3(x - 4)]}{x(x - 4) +2(x - 4)} [/tex]

= [tex] \frac{x(x-4)(x+3)}{(x-4)(x+2)} [/tex]

= [tex] \frac{x(x+3)}{(x+2)} [/tex]