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A +17 nc charge is located at the origin. what is the strength of the electric field at the position (x,y)=(5.0cm,0cm)? express your answer using

Respuesta :

meerkat18
The working equation to be used for this is written below:

E = kQ/d²
where
E is the electric field
k is a constant equal to 8.99 x 10⁹ N m²/C²
Q is the charge
d is the distance


E = (8.99 x 10⁹ N m²/C²)(17×10⁻⁹ C)/(0.05 m)²
E = 61,132 N/C

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