Answer:
Explanation:
It is given that, the velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds.
i.e. The initial velocity of the ball is, u = 20 m/s
Final velocity of the ball is, v =0
Time taken, t =3.5 s
The rate of change of velocity w.r.t time is called the acceleration of the ball.
So, [tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{0-20}{3.5}[/tex]
[tex]a=-5. 71\ m/s^2[/tex]
Hence, the average acceleration of the ball during its upward flight is [tex]a=-5. 71\ m/s^2[/tex].
